Termination w.r.t. Q of the following Term Rewriting System could be proven:

Q restricted rewrite system:
The TRS R consists of the following rules:

g3(x, a, b) -> g3(b, b, a)

Q is empty.


↳ QTRS
  ↳ Non-Overlap Check

Q restricted rewrite system:
The TRS R consists of the following rules:

g3(x, a, b) -> g3(b, b, a)

Q is empty.

The TRS is non-overlapping. Hence, we can switch to innermost.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof

Q restricted rewrite system:
The TRS R consists of the following rules:

g3(x, a, b) -> g3(b, b, a)

The set Q consists of the following terms:

g3(x0, a, b)


Using Dependency Pairs [1,13] we result in the following initial DP problem:
Q DP problem:
The TRS P consists of the following rules:

G3(x, a, b) -> G3(b, b, a)

The TRS R consists of the following rules:

g3(x, a, b) -> g3(b, b, a)

The set Q consists of the following terms:

g3(x0, a, b)

We have to consider all minimal (P,Q,R)-chains.

↳ QTRS
  ↳ Non-Overlap Check
    ↳ QTRS
      ↳ DependencyPairsProof
        ↳ QDP
          ↳ DependencyGraphProof

Q DP problem:
The TRS P consists of the following rules:

G3(x, a, b) -> G3(b, b, a)

The TRS R consists of the following rules:

g3(x, a, b) -> g3(b, b, a)

The set Q consists of the following terms:

g3(x0, a, b)

We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph [13,14,18] contains 0 SCCs with 1 less node.